calculus
posted by Anonymous on .
The radius of a spherical balloon is increasing at a rate of 2 centimeters per minute. How fast is the volume changing when the radius is 8 centimeters?
Note: The volume of a sphere is given by 4(pi)r^3

So, if V = 4/3 pi r^3
dV = 4 pi * r^2 dr
dV = 4 pi * 8^2 * 2
= 512 pi cc/min