Posted by echus on Monday, October 3, 2011 at 3:39pm.
The bases of a trapezoid are 38 and 17 respectively. The angles at the extremities of the larger base are 57 degrees and 45 degrees. find the two legs.

geometry  Steve, Monday, October 3, 2011 at 4:14pm
The total base under the triangles is 21 (3817)
Let b = the base by the 57° angle
So, the height
h = b*tan 57 = (21b) tan(45) = 21b
1.54b = 21b
b = 8.27
21b = 12.73
h = 12.73

geometry  bobpursley, Monday, October 3, 2011 at 4:17pm
now, having the height, use either sine or cosine to find the legs.

geometry  Dwinson, Wednesday, January 25, 2017 at 6:06am
6.65
9.38
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