Posted by **echus** on Monday, October 3, 2011 at 3:39pm.

The bases of a trapezoid are 38 and 17 respectively. The angles at the extremities of the larger base are 57 degrees and 45 degrees. find the two legs.

- geometry -
**Steve**, Monday, October 3, 2011 at 4:14pm
The total base under the triangles is 21 (38-17)

Let b = the base by the 57° angle

So, the height

h = b*tan 57 = (21-b) tan(45) = 21-b

1.54b = 21-b

b = 8.27

21-b = 12.73

h = 12.73

- geometry -
**bobpursley**, Monday, October 3, 2011 at 4:17pm
now, having the height, use either sine or cosine to find the legs.

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