Posted by echus on .
The bases of a trapezoid are 38 and 17 respectively. The angles at the extremities of the larger base are 57 degrees and 45 degrees. find the two legs.
Monday, October 3, 2011 at 4:14pm
The total base under the triangles is 21 (38-17)
Let b = the base by the 57° angle
So, the height
h = b*tan 57 = (21-b) tan(45) = 21-b
1.54b = 21-b
b = 8.27
21-b = 12.73
h = 12.73
Monday, October 3, 2011 at 4:17pm
now, having the height, use either sine or cosine to find the legs.
Wednesday, January 25, 2017 at 6:06am