Posted by echus on .
The bases of a trapezoid are 38 and 17 respectively. The angles at the extremities of the larger base are 57 degrees and 45 degrees. find the two legs.

geometry 
Steve,
Monday, October 3, 2011 at 4:14pm
The total base under the triangles is 21 (3817)
Let b = the base by the 57° angle
So, the height
h = b*tan 57 = (21b) tan(45) = 21b
1.54b = 21b
b = 8.27
21b = 12.73
h = 12.73 
geometry 
bobpursley,
Monday, October 3, 2011 at 4:17pm
now, having the height, use either sine or cosine to find the legs.

geometry 
Dwinson,
Wednesday, January 25, 2017 at 6:06am
6.65
9.38