Posted by terra on Monday, October 3, 2011 at 3:15pm.
y = 16^(sin x)
ln y = sin x * ln 16
1/y y' = ln 16 * cos(x)
y' = ln 16 * cos x * 16^(sin x)
In general, d/dx (e^u) = e^u du/dx
d/dx (a^u) = ln a * a^u du/dx
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