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posted by terra Monday, October 3, 2011 at 3:15pm.
how do i find the derivative of 16^(sinx)
y = 16^(sin x) ln y = sin x * ln 16 1/y y' = ln 16 * cos(x) y' = ln 16 * cos x * 16^(sin x) In general, d/dx (e^u) = e^u du/dx d/dx (a^u) = ln a * a^u du/dx
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