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February 27, 2015

February 27, 2015

Posted by **terra** on Monday, October 3, 2011 at 3:15pm.

- calc -
**Steve**, Monday, October 3, 2011 at 4:06pmy = 16^(sin x)

ln y = sin x * ln 16

1/y y' = ln 16 * cos(x)

y' = ln 16 * cos x * 16^(sin x)

In general, d/dx (e^u) = e^u du/dx

d/dx (a^u) = ln a * a^u du/dx

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