Posted by terra on .
how do i find the derivative of 16^(sinx)

calc 
Steve,
y = 16^(sin x)
ln y = sin x * ln 16
1/y y' = ln 16 * cos(x)
y' = ln 16 * cos x * 16^(sin x)
In general, d/dx (e^u) = e^u du/dx
d/dx (a^u) = ln a * a^u du/dx