Fibonacci Numbers
posted by Jennifer on .
This is not a test question, but I did not know what the appropriate topic for my question is.
If I used the terms 2, 3, 4, 8 consecutive terms of the Fibonacci sequence. "a" is the first and fourth terms and "b" is twice the product of the second and third terms. "c" will be the sum of the squares of the second and third terms.
I think I need to set the problem with the equation a^2 + b^2 = c^2
6^2 + 14^2 =
36+196=232
I do not think that I am doing this correctly and could use some help.

I love the Fibonacci sequence, but I can't make any sense out of your question
First of all the consecutive terms of the sequence would be
2, 3, 5, 8, 13, ....
According to you , "a" is 2 "and" 8 . Are we adding them? , ok, so a = 10
b = 2(3)(5) = 30
c = 9 + 25 = 34
is 10^2 + 30^2 = 34^2
no, it is not
How did you get the numbers 6 and 14???? 
I think it is the fibonacci numbers and the wording of the word problem. I thought I had to add 4 and 2 together to get the 6 and then square it. I am just confused. Thanks

You did not read my reply carefully.
We form a new Fibonacci number by adding the two previous numbers, so 4 does not fit the pattern,
The 4 should have been a 5.
Please type the question exactly the way it appeared. 
Thank you Jennifer! I just figured out where I went wrong in wording the problem.
a= 2x8=16
b=2x15=30
c=9+25=34
16^2+30^2=34^2
256+900=1156
1156=1156
Thank you for helping to guide me in the right direction.
One more problem to go by Friday...I just may be calling on you!