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January 25, 2015

January 25, 2015

Posted by **Susana** on Monday, October 3, 2011 at 1:03pm.

- Calculus -
**Reiny**, Monday, October 3, 2011 at 2:27pmequation:

s = -16t^2 - 22t + 220

v = ds/dt = -32t - 22

so at t=3

v = -16(3) - 22 = -70 ft/sec

when s = 108

108 = -16t^2 - 22t + 220

16t^2 + 22t - 112 = 0

t = (-22 ± √7652)/32 = 2.046 sec or a negative time

so when t = 2.046

v = -16(2.046) - 22 = - 54 ft/s

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