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March 1, 2015

March 1, 2015

Posted by **Katty** on Monday, October 3, 2011 at 1:50am.

- Math -
**PsyDAG**, Monday, October 3, 2011 at 1:17pmWhat do you mean by unusual? P < .10? P < .05? P < .01?

Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√(n-1)

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion for that Z score.

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