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A rocket is launched straight up with a constant acceleration. Three seconds after lift off, a small part of the rocket falls off the side. The small part hits the ground 7 seconds later. Ignoring air resistance, what was the acceleration of the rocket?

  • physics -

    Initial velocity of fragment, at release
    Vo = 3 a
    Height where fragment is released:
    H = (a/2)t^2 = (9/2)a

    Since Time to reach ground = 7s:
    y(t=7) = H +Vo*7 -(g/2)*49 = 0

    (9/2)a + 21a -24.5g = 0
    a = (24.5/25.5) g = 9.4 m/s^2

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