physics
posted by randy on .
An automobile starts from rest and accelerates to a final velocity in two stages along a straight road. Each stage occupies the same amount of time. In stage 1, the magnitude of the car's acceleration is 2.03 m/s2. The magnitude of the car's velocity at the end of stage 2 is 4.87 times greater than it is at the end of stage 1. Find the magnitude of the acceleration in stage 2.

Vf1 = Vo + at,
Vf1 = 0 + 2.03t = 2.03t.
Vf2 = 2.03t + 4.87*2.03t = 11.92t,
Vf2 = at = 11.92t,
at = 11.92t,
Divide both sides by t:
a = 11.92m/s^2=acceleration in stage 2.