Posted by randy on Monday, October 3, 2011 at 12:00am.
The space between the knights diminishes at a rate 0.530 m/s^2
Collision occurs when
(1/2)*0.530 t^2 = 72.6 m
t^2 = 274
t = 16.55 s
George will have moved
(1/2)*0.280*t^2 = 38.35 m
from his initial position at that time -- a bit more than half the initial separation.
Related Questions
physics - In a historical movie, two knights on horseback start from rest 93 m ...
physics - In a historical movie, two knights on horseback start from rest 60 m ...
physics - In an historical movie, two knights on horseback start from rest 90.6 ...
Physics - In a historical movie, two knights on horseback start from rest 64 m ...
physics - In a historical movie, two knights on horseback start from rest 62 m ...
physics - In a historical movie, two knights on horseback start from rest 91 m ...
Physics - In a historical movie, two knights on horseback start from rest 94m ...
Physics - In a historical movie, two knights on horseback start from rest 88.0m ...
Physics - Two knights on horseback start from rest 88.0 m apart and ride ...
physics - I still need help with this please.two knights on horseback start from...
For Further Reading