Posted by **SW** on Sunday, October 2, 2011 at 11:56pm.

Suppose the Sun were twice as massive as it actually is. What would be the orbital period of a planet at a distance of 10AU from the Sun?

- Astronomy -
**drwls**, Monday, October 3, 2011 at 5:40am
For the actual sun's mass, according to Kepler's third law,

P^2/a^3 = 1 = P^2/1000

P = 31.6 years

For a sun that is twice as massive, the centripetal gravity force is twice as large, so V must increase by a factor of sqrt2 to balance it.

The period will be lower by a factor 1/sqrt2 due to the higher speed

Period = 31.6/1.414 = 22.4 years

## Answer this Question

## Related Questions

- astronomy - suppose teh sun were twice as massive a it actually is. What would ...
- physics - The physics of orbital radius and orbital period of a planet. If a ...
- Astronomy - Orbital speed is the speed with which a planet moves around the sun...
- Astro - A newly discovered planet orbits a distant star with the same mass as ...
- Math - The period of revolution of a planet around the sun is the time it takes ...
- physics - The mean distance of the planet Neptune from the Sun is 30.05 times ...
- Physics - A certain planet is located 3.54 x 10^11 m from its sun. If its ...
- Physics - A certain planet is located 3.54 x 10^11 m from its sun. If its ...
- Physics - A certain planet is located 3.54 x 10^11 m from its sun. If its ...
- urgent (physics) - A certain planet is located 3.54 x 10^11 m from its sun. If ...