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July 30, 2014

July 30, 2014

Posted by **Peter** on Sunday, October 2, 2011 at 11:46pm.

I tried graphing this, which formed a parallelogram, but it was hard to find eyeball vertices.

- Algebra 2 -
**Steve**, Monday, October 3, 2011 at 10:23amThat's what algebra is for. Pair up the equations to fin the intersections:

3x+4y = 12

5x+6y = 30

x = -16 and y = 15

and likewise for the others. No eyeballing needed.

- Algebra 2 -
**Peter**, Tuesday, October 4, 2011 at 12:40amShouldn't it have 4 points due to 4 vertices?

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