Thursday

November 27, 2014

November 27, 2014

Posted by **Shelby** on Sunday, October 2, 2011 at 11:36pm.

**Leibniz's rule: If g(x) and h(x) are differentiable functions and f(u) is continuous for u between g(x) and h(x), then

d/dx of the integral from g(x) to h(x) of f(u) du = f[h(x)]h'(x) - f[g(x)]g'(x)

y = the integral from 2+x² to 2 of (cot t) dt

- Calculus -
**Steve**, Monday, October 3, 2011 at 10:21amWhat's to worry about? You have the formula, just plug in f,g,h. The only possible sticking spot is knowing that Int(cot(t) dt] = ln sin t

**Answer this Question**

**Related Questions**

math - can anybody explain me what the Leibniz Integral Rule is?

math - I heard that when we are proving Leibniz's formula for differentiating an...

Philosophy - Leibniz presents monads as simple substances. Monads are infinite ...

mathematics - can anybody tell me how the Leibniz's rule for the differentiation...

Calculus - If y = y(x), write y’ in Leibniz notation.

Math - Calculus Question. - hey can someone explain to me the relationship ...

Self-Taught Mathematicians - Those of us who love math certainly know two basic ...

Calculus - Match the rule with the title: ____ 3. d/dx [f(x)/g(x) ]=(g(x) f^' (x...

calc - Which of the following statements would always be true? I. If f is ...

Calculus - How do I use the chain rule to find the derivative of square root(1-x...