October 10, 2015

Homework Help: chemistry

Posted by Holly on Sunday, October 2, 2011 at 9:42pm.

Calculate the pH at the point in the titration of 25.00 mL 0.108 M HNO2 at which 10.00 mL 0.162 M NaOH have been added. For HNO2, Ka=5.1 x 10^-4 and:

HNO2 + OH- -----> H2O + NO2-

I know that HNO2 is a weak acid and that 5.1 x 10^-4=[NO2-]/[HNO2][OH-]. NaOH is a strong acid . Not sure how to go from here. Thanks.

Answer this Question

First Name:
School Subject:

Related Questions

More Related Questions