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September 24, 2014

September 24, 2014

Posted by **Luke** on Sunday, October 2, 2011 at 6:36pm.

- college physics -
**bobpursley**, Sunday, October 2, 2011 at 6:42pmwhen w^2 r= g

w= sqrt (g/r) and w is in rad/sec.

w (in rev/min)= w above * 60/2PI

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