what are the number of turning points for this equation? y=4x^2
and can you plz explain how u find them thanks :)
1. Looking at the graph, you see when the fuunction switches from increasing to decreasing, or vice versa; you're checking its concavity
so the answer wud b 1?
To find the number of turning points for the equation y = 4x^2, we need to understand what a turning point is and how to identify them.
A turning point is a point on the graph where the curve changes direction, either from increasing to decreasing or from decreasing to increasing. In other words, it is a point where the slope of the curve changes sign.
To determine the number of turning points for the equation y = 4x^2, we need to consider the behavior of the quadratic function.
For any quadratic function of the form y = ax^2 + bx + c, the number of turning points is determined by the coefficient in front of the x^2 term (in this case, 4).
- If the coefficient is positive, as it is in this case, the parabola opens upward (U-shaped) and has a single minimum point.
- If the coefficient is negative, the parabola opens downward (n-shaped) and has a single maximum point.
With y = 4x^2, since the coefficient (4) is positive, the parabola opens upward and has a single minimum point (turning point). Therefore, the number of turning points for this equation is 1.
In summary, for the equation y = 4x^2, there is one turning point which is a minimum point.