Mg3N2 +6H2O- 3Mg(OH)2 + 2NH3-- How many grams of H2O are needed to produce 150g of Mg(OH)2?
I thought I had this but.....the correct answer should be 93 grams
Where did I go wrong??
1) Change 150 g Mg(OH)2 into moles by dividing by molar mass from periodic table.
150 / (24 + 32 + 3) = moles
2) Ratio of chemicals is 6 H2O to 3 Mg(OH)2 - Multiply the #moles Mg(OH)2 by 3/6 which is the ratio of moles H2O to Mg(OH)2.
3) multiply by the mass of H2O from the periodic table. The mass of H2O is 18.
But.. the answer should be 93 grams
Thanks for your help!
I got it I take 18 and multiple by 5.172=93.1 g
To find the correct amount of water (H2O) needed to produce 150g of Mg(OH)2, you need to go through the steps again, but with some adjustments.
1) Calculate the moles of Mg(OH)2:
150g / (24 + 32 + 16 + 16) g/mol = moles of Mg(OH)2
2) The balanced equation indicates that the ratio of H2O to Mg(OH)2 is 6:3, or simplified, 2:1. Multiply the moles of Mg(OH)2 by this ratio (2/1) to get the moles of water needed.
3) Multiply the moles of water by the molar mass of H2O to obtain the grams of water required.
Let's calculate it step-by-step:
1) Moles of Mg(OH)2:
150g / (24 + 32 + 16 + 16) g/mol = 150g / 74 g/mol = 2.03 moles
2) Moles of H2O needed:
2.03 moles * (2 moles H2O / 1 mole Mg(OH)2) = 4.06 moles H2O
3) Grams of H2O:
4.06 moles * 18 g/mol = 73.08 grams of H2O
Thus, the correct answer is approximately 73 grams of H2O, not 93 grams.
It seems like you made a small mistake in step 2. The correct ratio of H2O to Mg(OH)2 in the balanced chemical equation is 6 moles of H2O to 3 moles of Mg(OH)2.
Let's go through the steps again to find the correct answer:
1) Convert 150 g of Mg(OH)2 into moles. The molar mass of Mg(OH)2 is (24 + 16 + 1) + 2(1 + 16) = 58 g/mol.
So, moles = 150 g / 58 g/mol = 2.586 moles (rounded to three decimal places).
2) Use the ratio of H2O to Mg(OH)2 from the balanced chemical equation, which is 6 moles of H2O to 3 moles of Mg(OH)2.
Multiply the moles of Mg(OH)2 by (6/3) to get the moles of H2O.
Moles of H2O = 2.586 moles * (6/3) = 5.172 moles (rounded to three decimal places).
3) Multiply the moles of H2O by the molar mass of H2O to get the mass of H2O.
Mass of H2O = 5.172 moles * 18 g/mol = 93.096 grams (rounded to three decimal places).
Therefore, you need approximately 93 grams of H2O to produce 150 grams of Mg(OH)2.