Write a balanced equation for copper oxide + Ethanoic Acid
CH3COOH
To write a balanced equation for the reaction between copper oxide and ethanoic acid, we need to know the molecular formulas of both compounds.
The molecular formula of copper oxide is CuO, and the formula of ethanoic acid is CH₃COOH.
The balanced equation for the reaction between copper oxide and ethanoic acid can be written as:
CuO + 2 CH₃COOH → Cu(CH₃COO)₂ + H₂O
In this equation, one molecule of copper oxide reacts with two molecules of ethanoic acid to produce one molecule of copper(II) acetate (Cu(CH₃COO)₂) and one molecule of water (H₂O).
To write a balanced equation for the reaction between copper oxide (CuO) and ethanoic acid (CH3COOH), we need to identify the elements involved and their respective charges.
The chemical formula for copper oxide is CuO, where copper has a charge of +2 and oxygen has a charge of -2. The formula for ethanoic acid is CH3COOH, and it consists of carbon (C), hydrogen (H), and oxygen (O).
Now, let's write the balanced equation step by step:
Step 1: Write the chemical formula for copper oxide and ethanoic acid:
CuO + CH3COOH
Step 2: Split the compounds into their respective ions:
Cu2+ + O2- + CH3COOH
Step 3: Identify the exchange of ions during the reaction:
Cu2+ from CuO will combine with CH3COO- from CH3COOH to form the product Cu(CH3COO)2.
Step 4: Write the balanced equation:
CuO + 2CH3COOH → Cu(CH3COO)2 + H2O
The balanced equation for the reaction between copper oxide and ethanoic acid is CuO + 2CH3COOH → Cu(CH3COO)2 + H2O.