Find where the two slanting lines intersect:
-x/2 + 5 = 6x
x = 10/13
That's the height of a triangle with base on the y-axis, length 5.
Area = 5 * 10/13 = 50/13
the height = b
the width is where y=0: x = -b/m
Area = b * -b/m = -b^2/m
where do they intersect?
mx+5 = x
x = 5/(1-m)
That's the height of the triangle with base on the y-axis, length 5
Area = 5/(1-m) * 5 = 25/(1-m)
25/(1-m) = 10
25 = 10m - 10
m = 35/10 = 3.5
a) -x/2 +5 = 6x
A= 1/2 (b)(h)
A= 1/2 (10/13)(5)= 25/13
width= x =-b/m
A= 1/2 (-b/m)(b)= -b^2/2m
10=1/2 (5) (5/(1-m))
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