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Chemistry

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An aqueous solution with a density of 0.998 g/ml at 20 degrees Celsius is prepared by dissolving 12.8 mL of CH3CH2CH2OH (p=0.803 g/mL) in enough water to make 75.0 mL of solution calculate the molarity

  • Chemistry - ,

    grams CH3CH2CH2OH = volume x density = 12.8 x 0.803 = ?
    moles CH3CH2CH2OH = grams/molar mass
    Then M = moles/L soln.
    L soln = 0.075L

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