Homework Help: Chemistry

Posted by Jessica on Saturday, October 1, 2011 at 7:32pm.

An aqueous solution with a density of 0.998 g/ml at 20 degrees Celsius is prepared by dissolving 12.8 mL of CH3CH2CH2OH (p=0.803 g/mL) in enough water to make 75.0 mL of solution calculate the molarity

Chemistry - DrBob222, Saturday, October 1, 2011 at 11:50pm
grams CH3CH2CH2OH = volume x density = 12.8 x 0.803 = ?
moles CH3CH2CH2OH = grams/molar mass
Then M = moles/L soln.
L soln = 0.075L

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