Posted by anonymous on Saturday, October 1, 2011 at 7:10pm.
I used 60.096 for the molar mass of the alcohol and 78 .54 for the molar mass of the 1-chloropropane and I obtained 98.01817. You are allowed 4 s.f. so I would round my answer to 98.02 grams.
#2 is 3.60 and you are allowed 3 s.f.
#3. I don't think so.
You want moles Na = 1.43M x 0.250 = ?
moles Na3PO4 = moles Na/3 = ?
M Na3PO4 = moles Na3PO4/L Na3PO4 = about 32 mL. You are allowed 3 s.f.
#4 is ok. Are you having trouble with s.f.? Here is a link that should help.
http://www.chemteam.info/SigFigs/SigFigs.html
are you sure about number 4? shouldn't it have 3 significant digits because of the 75.0 ml ?
are you sure about number 4? shouldn't it have 3 significant digits because of the 75.0 ml ?
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