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March 26, 2017

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You shoot an arrow into the air. 2.oo seconds later the arrow has gone straight upward to a height of 30 meters above its launch point. (a) What was the arrow's initial speed? (b) How long did it take for the arrow to first reach a height of 15 meters above it's launch point?

  • Physics - ,

    Y = Vo*t -(g/2)t^2
    At t = 2.00s,
    30 = 2*Vo -(4.9)*4
    (a) Vo = 24.8 m/s

    (b) Now that you know Vo, use the first equation again to solve for t when Y = 15 m.

  • Physics - ,

    3.45

  • Physics - ,

    5.6

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