A body is projected vertically upwards at a speed of 63m/s. if g = 9.8m/ s². Find the maximum height reached?
It reaches maximum height, H, when the initial kinetic energy (1/2)MVo^2 equals the potential enmergy gain mgH.
At that time,
H = Vo^2/(2g)
A projectile of mass 40g is fired vertically and reached a maximum height of 40m.calculate the potential energy at highest point(g=10m/s-2)
To find the maximum height reached by the body, we can use the kinematic equation for vertical motion:
h = (v₀² - v²) / (2g)
Where:
h = maximum height reached
v₀ = initial velocity (63 m/s)
v = final velocity (0 m/s when the body reaches maximum height)
g = acceleration due to gravity (9.8 m/s²)
Plugging in the values, we have:
h = (63² - 0²) / (2 * 9.8)
Calculating further:
h = (3969 - 0) / 19.6
h = 3969 / 19.6
h ≈ 202.5 meters
Therefore, the maximum height reached by the body is approximately 202.5 meters.