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November 25, 2014

November 25, 2014

Posted by **Norman** on Saturday, October 1, 2011 at 10:57am.

The resistive force acting on the dragster is f=-Av^2

you know the following

m=1000kg

v= speed of the dragster at any time after stickman crosses the finish line

vi=100m/s=speed of the dragster as stickman crosses the finish line

g=acceleration due to gravity

1)write newton's second law equation for the dragster any time after stickman crosses the finish line.

2) solve newton's second law equation to determine an expression for the area of the parachute attacked to the dragster at any time after stickman crossest eh finish line.

3)determine the diameter of the parachute needed to slow the dragster down from 100m/s to 10m/s in 10s.

- physics -
**William King**, Sunday, October 2, 2011 at 5:33pm#1. 1/Vf-1/Vo=(A/m)tf

#2 just solve for a

#3 Plug in. A=9m^2 then plug into formula and solve for d

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