Monday

October 20, 2014

October 20, 2014

Posted by **Norman** on Saturday, October 1, 2011 at 10:57am.

The resistive force acting on the dragster is f=-Av^2

you know the following

m=1000kg

v= speed of the dragster at any time after stickman crosses the finish line

vi=100m/s=speed of the dragster as stickman crosses the finish line

g=acceleration due to gravity

1)write newton's second law equation for the dragster any time after stickman crosses the finish line.

2) solve newton's second law equation to determine an expression for the area of the parachute attacked to the dragster at any time after stickman crossest eh finish line.

3)determine the diameter of the parachute needed to slow the dragster down from 100m/s to 10m/s in 10s.

- physics -
**William King**, Sunday, October 2, 2011 at 5:33pm#1. 1/Vf-1/Vo=(A/m)tf

#2 just solve for a

#3 Plug in. A=9m^2 then plug into formula and solve for d

**Answer this Question**

**Related Questions**

physics - Stickman is driving a dragster. He does the quarter mile in 4 seconds ...

Physics - A dragster travels 1/4 mile in 6.1 seconds. Assuming the acceleration...

Physics - A dragster accelerates from rest for a distance of 450m at 14 m/s^2. A...

Physics - A dragster accelerates from rest for a distance of 450m at 14 m/s^2. A...

Physics - A dragster accelerates from rest for a distance of 450m at 14 m/s^2. A...

physics - Secretariat ran the Kentucky Derby with times for the quarter mile of ...

physics - A top fuel dragster covers the quarter mile in 4.5 seconds. what is ...

algebra 2 - 15 seconds after the buzzer, the teacher still has 135 meters to go ...

physics - Consider an object on which the net force is a resistive force ...

Math - Runner A crosses the starting line of a marathon and runs at an average ...