Posted by Anonymous on Friday, September 30, 2011 at 8:38pm.
I got lost at this part. I'm not sure what to do now, if i am solving it correctly.
I was not sure where to go from here. This is most likely incorrect, the way I am solving it.
- Algebra 2 - Reiny, Friday, September 30, 2011 at 10:24pm
4a-2 ≤ a+1 ≤ 3a+4
4a-2 ≤ a+1 AND a+1 ≤ 3a+4
3a ≤ 3 AND -2a ≤ 3
a ≤ 1 AND a ≥ -3/2
so : -3/2 ≤ a ≤ 1
0 < 4-8x < 5
-4 < -8x < 1
1/2 > x > -1/8
-1/8 < x < 1/2
the reason I did not have to split up the second is that we could subtract 3x from both ends and the x's disappeared.
I had to split up the first, since I could not eliminate the x's from both ends.
- Algebra 2 - Anonymous, Saturday, October 1, 2011 at 12:19am
Thank you so much.
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