At 1:00 p.m. a car, traveling at a constant

velocity of 96 km/h toward the west, is 24 km
to the west of our school.
How far from the school will it be at 3:30
p.m.?
Answer in units of km.

I've been attempting this problem for at least 30 minutes and not getting the right answer. Help? Thanks!

car travels west.

from 1:00 to 3:30 is 1.5 hours.
speed is 96km/h.
so, in that 1.5 hours, it travels 144 km.

at 1:00 it was already 24km away.
So, 1.5 hours later it is now 24+144 = 168km away.

3.666

To determine how far the car will be from the school at 3:30 p.m., we can use the formula:

Distance = Rate x Time

Given that the car is traveling at a constant velocity of 96 km/h toward the west, we can calculate the distance it has covered from 1:00 p.m. to 3:30 p.m.

Step 1: Calculate the time difference between 1:00 p.m. and 3:30 p.m.

3:30 p.m. - 1:00 p.m. = 2.5 hours

Step 2: Calculate the distance covered in 2.5 hours.

Distance = Rate x Time
Distance = 96 km/h x 2.5 hours

Step 3: Calculate the total distance from the school.

Total distance = Distance covered + Initial distance from the school

Total distance = (96 km/h x 2.5 hours) + 24 km

Now we can calculate the total distance.

Total distance = (96 km/h x 2.5 hours) + 24 km
Total distance = 240 km + 24 km
Total distance = 264 km

Therefore, at 3:30 p.m., the car will be 264 km from the school.

To solve this problem, you can use the formula: distance = velocity × time.

Given that the car is traveling at a constant velocity of 96 km/h toward the west, we know its speed is consistent. Therefore, we can use the formula to find the distance the car travels between 1:00 p.m. and 3:30 p.m.

To calculate the time difference, we need to find the time elapsed between 1:00 p.m. and 3:30 p.m.

1:00 p.m. to 2:00 p.m. is 1 hour.
2:00 p.m. to 3:00 p.m. is another hour.
3:00 p.m. to 3:30 p.m. is 30 minutes, which is half an hour.

The total time elapsed is 1 + 1 + 0.5 = 2.5 hours.

Now, we can calculate the distance using the formula:

distance = velocity × time
distance = 96 km/h × 2.5 hours
distance = 240 km

Therefore, the car will be 240 km from the school at 3:30 p.m.