What is the molarity of a solution containing 8 grams of solute in 500 mL of solution? Round to the nearest hundredth. Don't forget the unit! (gram formula mass of solute = 24 g)
0.67
To find the molarity of a solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution in liters
First, we need to convert the given mass of solute (8 grams) to moles using the formula:
moles = mass / molar mass
The molar mass of the solute is given as 24 g.
moles = 8 g / 24 g/mol
moles = 0.33333 mol
Next, we need to convert the given volume of solution (500 mL) to liters:
volume = 500 mL / 1000 mL/L
volume = 0.5 L
Now, we can substitute the values into the molarity formula:
Molarity (M) = 0.33333 mol / 0.5 L
Molarity = 0.66666 M
Rounded to the nearest hundredth, the molarity of the solution is 0.67 M (Molar).
To find the molarity of a solution, you need to divide the number of moles of solute by the volume of the solution in liters.
First, let's calculate the number of moles of solute in 8 grams.
To do this, we divide the mass of the solute by its gram formula mass. In this case, the gram formula mass of the solute is given as 24 g.
Number of moles of solute = Mass of solute / Gram formula mass
Number of moles = 8 g / 24 g
Next, we need to convert the volume of the solution from milliliters to liters.
There are 1000 milliliters in a liter.
Volume of solution in liters = 500 mL / 1000 mL/L
Volume of solution = 0.5 L
Now we can calculate the molarity.
Molarity (mol/L) = Number of moles of solute / Volume of solution in liters
Molarity = (8 g / 24 g) / 0.5 L
Calculating this expression gives us the molarity of the solution. Let's round the result to the nearest hundredth:
Molarity = 0.333333333 mol/L
Rounding to the nearest hundredth, the molarity of the solution containing 8 grams of solute in 500 mL of solution is approximately 0.33 mol/L.
moles = grams/gram formula mass
M = moles/L soln (Lsoln = 0.500L)