Posted by **Anonymous** on Friday, September 30, 2011 at 12:35pm.

A stone is thrown from ground level at 70m/s. Its speed when it reaches its highest point is 48 m/s. Find the angle, above the horizontal, of the stone’s initial velocity.

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**Steve**, Friday, September 30, 2011 at 1:23pm
Check me on this, I'm a little rusty.

The initial velocity is 70. Since the horizontal speed never changed, that means that the x-component was 48. So, cos θ = 48/70, so θ = 46.7°

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**Jimmy**, Friday, September 30, 2011 at 6:38pm
thank you

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