Tuesday

June 28, 2016
Posted by **stellar** on Friday, September 30, 2011 at 12:35pm.

(a) Find the distance of the plane from point A.

mi

(b) Find the elevation of the plane.

mi

- trig -
**Anonymous**, Friday, September 30, 2011 at 12:44pmlet me start you off

draw a straight line representing 4miles apart..... now at the ends of the line make angles of 27 and 53

now figure it out - trig -
**stellar**, Friday, September 30, 2011 at 12:48pmi don't get it

- trig -
**swag**, Tuesday, March 3, 2015 at 7:11pmI'm strugglin so hard on this

- trig -
**Aspen**, Tuesday, March 3, 2015 at 7:34pmI THINK I GOT IT

okay so draw a triangle (not a right triangle)

the bottom number is 4

draw an imaginary line straight down from the tip of the triangle to the bottom

half a circle is 180. so the total middle area of the triangle is 180-27-53 which is 100.

keep in mind that 27 and 53 are the ANGLES OF DEPRESSION. so draw a straight line across the top of your triangle and the area between this straight top line and the side of your triangle is the angle of depression.

now look at your imaginary line.

we know that 1/4 of a triangle is 90 deg

90-27=63.

so your top angle in THIS HALF of the triangle is 63degrees

basically treat each half like 2 different triangles.

we can determine the 3rd angle (i have this marked as A) by 180-90-63 (the 90 is where our straight line down is)

so we know that A is 27

now we have all 3 angles to one side of our triangle

now repeat this process to the other half of the triangle

(keep in mind we can NOT divide the 4 miles)

so we should have 90, 37 and 53 for triangle half #2.

NOW look at the triangle as one big triangle

the top is 180, the sides are 27 and 53

the bottom length is 4

look at this as a ASA triangle

27deg, 4, 53deg

now use law of sines

a/sinA= c/sinC

plug in numbers

a/sin27= 4/sin180

now a= (4x sin27)/ sin180

plug that into your calculator and you have side a

repeat this to find side b

the answer to your first question will be the length of side b

for the second question you need to take these same numbers

divide your triangle in half again

solve for the new "side a" aka the line you drew down the middle

tada you have your answers!

yay math - trig -
**Aspen**, Tuesday, March 3, 2015 at 7:43pmHOLD UP HOLD UP

okay sorry y'all one minor error.... ignore my last post here is the new and improved and correct explanation

I THINK I GOT IT

okay so draw a triangle (not a right triangle)

the bottom number is 4

draw an imaginary line straight down from the tip of the triangle to the bottom

half a circle is 180. so the total middle area of the triangle is 180-27-53 which is 100.

keep in mind that 27 and 53 are the ANGLES OF DEPRESSION. so draw a straight line across the top of your triangle and the area between this straight top line and the side of your triangle is the angle of depression.

now look at your imaginary line.

we know that 1/4 of a triangle is 90 deg

90-27=63.

so your top angle in THIS HALF of the triangle is 63degrees

basically treat each half like 2 different triangles.

we can determine the 3rd angle (i have this marked as A) by 180-90-63 (the 90 is where our straight line down is)

so we know that A is 27

now we have all 3 angles to one side of our triangle

now repeat this process to the other half of the triangle

(keep in mind we can NOT divide the 4 miles)

so we should have 90, 37 and 53 for triangle half #2.

NOW look at the triangle as one big triangle

the top is 100, the sides are 27 and 53

the bottom length is 4

look at this as a ASA triangle

27deg, 4, 53deg

now use law of sines

a/sinA= c/sinC

plug in numbers

a/sin27= 4/sin100

now a= (4x sin27)/ sin100

plug that into your calculator and you have side a

repeat this to find side b

the answer to your first question will be the length of side b

for the second question you need to take these same numbers

divide your triangle in half again

solve for the new "side a" aka the line you drew down the middle

tada you have your answers!

yay math