Posted by **Eric** on Friday, September 30, 2011 at 11:15am.

You and your friend are practicing pass plays with a football. You throw the football at a 35.0° angle above the horizontal at 19.0 m/s. Your friend starts right next to you, and he moves down the field directly away from you at 5.50 m/s. How long after he starts running should you throw the football? Assume he catches the ball at the same height at which you throw it.

- Physics -
**Henry**, Saturday, October 1, 2011 at 4:43pm
Vo = (19m/s,35 deg.).

Xo = hor.= 19cos35 = 15.56m/s.

Yo = ver.= 19sin35 = 10.90m/s.

h = (Vf^2 - Yo^2) / 2g,

h = (0 - (10.9)^2) / -19.6 = 6.06m.

t(up) = (Vf - Yo) / g,

t(up) = (0 - 10.9) / -9.8 = 1.11s.

t(dn) = t(up) = 1.11s.

T = t(up) + t(dn) = 1.1 + 1.11 = 2.22s

= Time in flight.

d = Xo*T = 15.56 * 2.22 = 34.5m = hor

distance traveled.

t = d/V = 34.5 / 5.5 = 6.27s

td + T = 6.27s,

td = 6.27 - T = 6.27 - 2.22 = 4.07s.

after the receiver starts running, the

ball should be thrown.

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