Monday

October 20, 2014

October 20, 2014

Posted by **Kaitlyn** on Friday, September 30, 2011 at 9:56am.

- Physics -
**tchrwill**, Friday, September 30, 2011 at 1:24pmThe escape velocity for any body may be calculated from Ve = sqrt[2µ/r] where Ve = the escape velocity in feet per second, µ = the gravitational constant of the body (1.407974x10^16 ft.^3/sec.^2 for Earth) and r = the surface distance in feet. For earth, with an equatorial radius of ~3963 miles r becomes 3963(5280) = ~20,924,640 feet and Ve = sqrt[2(1.407974x10^16)/20,924,640] = ? ft./sec. Divide your answer by 1.467 to get the answer in miles per hour.

For the moon, µ = 1.731837x10^14 ft.^3/sec.^2, r = 1080 miles = 5,702, 400 feet.

For the sun, µ = 4.68772x10^21 and r = 432,495 miles = 2,283,573,600 feet.

**Answer this Question**

**Related Questions**

Physics - How fast does a rocket need to be going to break free of Earth's ...

Physics - How fast would a rocket have to be going in order to completely leave ...

Physics - Posted earlier but I wrote it incorrectly. How fast would a rocket ...

physics - rollercoaste starts at 12m high with a v of 1.2m/s and climbs to 9.0m ...

physics - A 71.4 kg satellite orbits the earth at a distance of 7.00E6 m from ...

Physics - A typical model rocket has a mass of 50 g. Similarly, a typical "class...

physics - During a lift off , the thrust a rocket produces must overcome the ...

Physics - Use the following numbers for this question. MEarth 5.98e+24 kg ...

PHYSICS - Model rockets are lightweight rockets powered by very small engines. A...

motion,physics - Model rockets are lightweight rockets powered by very small ...