Sunday
March 26, 2017

Post a New Question

Posted by on .

A 2.40 kg mass, m, on a frictionless table is moving in a circle with radius 0.500 m at a constant speed. m is attached to a 5.70 kg mass, M, by a cord through a hole in the table. Find the speed with which m must move for M to stay at rest

  • Physics - ,

    I'm in this class too :/

    For this problem, you have to use both equations F=Ma and F=(mv^2)/r

    Step 1: solve for F using F=Ma
    5.70kg x 9.81 m/s^2 = 55.917 N

    Step 2: plug this into the other equation
    55.917N = (2.40kg x v^2)/0.500m
    (55.917N x .5m)/2.40kg
    =11.65 m^2/s^2
    (squareroot)11.65 = 3.41 m/s

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question