Thursday

November 27, 2014

November 27, 2014

Posted by **Mike** on Friday, September 30, 2011 at 12:59am.

- Physics -
**Jessi**, Friday, September 30, 2011 at 8:52pmI'm in this class too :/

For this problem, you have to use both equations F=Ma and F=(mv^2)/r

Step 1: solve for F using F=Ma

5.70kg x 9.81 m/s^2 = 55.917 N

Step 2: plug this into the other equation

55.917N = (2.40kg x v^2)/0.500m

(55.917N x .5m)/2.40kg

=11.65 m^2/s^2

(squareroot)11.65 = 3.41 m/s

**Answer this Question**

**Related Questions**

Physics - A 4.10 kg mass, m, on a frictionless table is moving in a circle with ...

Physics - A 3.50 kg mass, m, on a frictionless table is moving in a circle with ...

Physics - A 3.50 kg mass, m, on a frictionless table is moving in a circle with ...

Physics - A mass of 0.475 kg, on a frictionless table, is attached to a string ...

physics - A mass m1 = 6.0 kg sits on a frictionless table, and rotates at a ...

Physics - A 0.5 kg mass is moving in a circle of radius 1.8 m on a flat ...

physics - A 0.5 kg mass is moving in a circle of radius 1.8 m on a flat ...

Physics - A puck of mass m = 1.10 kg slides in a circle of radius r = 24.0 cm ...

Physics - A puck of mass m = 1.26 kg slides in a circle of radius r = 25.0 cm on...

physics - A small 0.533-kg object moves on a frictionless horizontal table in a ...