I need help balancing this problem
HClO3(aq excess) + CaCO3
I got to
HCO3 + CaCiO3
HClO3 + CaCO3 ==> H2O + CO2 + Ca(ClO3)2
I think you can balance it with the right products.
What does it mean by aq excess and is this something I need to pay attention to. Does it help me balance the equation
To balance the chemical equation HClO3(aq excess) + CaCO3, you need to ensure that the number of each type of atom is the same on both sides of the equation. Here's the step-by-step process to balance it:
1. Start by counting the number of each type of atom on both sides of the equation:
HClO3(aq excess) + CaCO3 --> HCO3 + CaCiO3
On the left-hand side (LHS):
H: 1
Cl: 1
O: 3
Ca: 1
C: 1
On the right-hand side (RHS):
H: 1
C: 1
O: 3
Ca: 1
2. Balance the atoms that appear in unequal numbers first. In this case, the Cl atom appears on the LHS but not on the RHS, and HCO3 appears on the RHS but not on the LHS.
HClO3(aq excess) + CaCO3 --> HCO3^- + CaClO3
On the left-hand side (LHS):
H: 1
Cl: 1
O: 3
Ca: 1
C: 1
On the right-hand side (RHS):
H: 1
C: 1
O: 3
Ca: 1
Cl: 1
3. Now, check for any remaining unbalanced atoms. In this case, there are no more. The equation is balanced!
The balanced equation for the reaction between HClO3(aq excess) and CaCO3 is:
HClO3(aq excess) + CaCO3 --> HCO3^- + CaClO3
Make sure to double-check the balancing to ensure accuracy.
To balance the chemical equation HClO3(aq excess) + CaCO3, you need to make sure that there is an equal number of atoms on both sides of the equation.
Let's start by counting the number of atoms on each side:
On the left side, we have 1 hydrogen (H), 1 chlorine (Cl), 3 oxygen (O), 1 calcium (Ca), and 1 carbon (C).
On the right side, we have 1 hydrogen (H), 1 carbon (C), 1 calcium (Ca), and 3 oxygen (O).
Looking at the equation, we see that there is an excess of hydrochloric acid (HClO3), so we can ignore it for now and focus on balancing the remaining part of the equation.
The unbalanced equation is:
HClO3 + CaCO3 → HCO3 + CaCiO3
To balance the equation, we can start with the calcium (Ca) on both sides. We already have 1 calcium on each side, so that is balanced.
Next, we move to the carbon (C). On the left side, we have 1 carbon (C), while on the right side, we have HCO3. This means we need 1 more carbon on the right side to balance it. To do this, we can put a coefficient of 1 in front of HCO3.
The balanced equation so far is:
HClO3 + CaCO3 → 1HCO3 + CaCiO3
Now, let's look at the hydrogen (H) atoms. On the left side, we have 1 hydrogen from HClO3, while on the right side, we currently have 0 hydrogen. To balance this, we can put a coefficient of 3 in front of HCO3.
The balanced equation becomes:
HClO3 + CaCO3 → 3HCO3 + CaCiO3
Lastly, we need to balance the oxygen (O) atoms. On the left side, we have 3 oxygen atoms from HClO3, while on the right side, we have 3 oxygen atoms from 3HCO3 and 3 oxygen atoms from CaCiO3. This gives us a total of 6 oxygen atoms on the right side. To balance this, we can put a coefficient of 2 in front of CaCO3.
The final balanced equation is:
2HClO3 + CaCO3 → 3HCO3 + CaCiO3
So, the balanced equation is 2HClO3 + CaCO3 → 3HCO3 + CaCiO3.