Posted by Robin on Thursday, September 29, 2011 at 9:53pm.
I will assume you meant
f(x) = 3x/(1 + x^2)
then by the quotient rule
f'(x) = ( 3(1 + x^2) - 3x(2x) )/(1 + x^2)^2
f'(4) = (3(17) - 12(8))/289 = -45/289
so now you have the slope m = -45/289
and your strange point (4, .70588)
Use your grade 9 method of y=mx + b
to find the equation.
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