Posted by Chandler on Thursday, September 29, 2011 at 9:47pm.
I must admit I don't know what an equimolar solution of HCl is; however, in the context of the problem I assume you are trying to say that the HCl and the KOH are the same molarity. I understand that two solutions can be equimolar but I don't know how one solution can be equimolar. At any rate, if the solutions have the same molarity and equal volumes are mixed, then moles acid exactly equal moles base, so you have neither HCl nor NaOH remaining but they have combined to produce a salt, NaCl, which completely dissociates in aqueous solution to form Na^+ and Cl^-. You also have water.
water, na+, cl-
ut
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