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December 19, 2014

December 19, 2014

Posted by **Maria** on Thursday, September 29, 2011 at 9:36pm.

y= -3/2x in quadrant 4

- Pre-calculus -
**Reiny**, Thursday, September 29, 2011 at 10:10pmlet x=2, then y = (-3/2)(2) = -3

then r^2 = 2^2 + (-3)^2 = 13

r = √13

sinØ = -3/√13 , cscØ = -√13/3

cosØ = 2/√13 , secØ = √13/2

tanØ = -3/2 , cotØ = -2/3

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