calculus
posted by Anonymous on .
Express the given quantity as a single logarithm.
1/3ln(x + 2)3 + 1/2[ln(x)− ln(x^2+3x+2)^2]

ln a + ln b+ klnc  ln d
ln [abc^{k} / d] 
A bit of manipulation reveals that it's just ln(sqrt(x)/(x+1))