Math
posted by Nemo .
y = f(x) = 5  x  3x^2
Find the yintercepts, xintercepts, and the vertex

y = 3^2  x + 5
y  int = 5
x int = 1.46 and 1.14 (using the quadratic equation of x = (b+/ sqrt(b^2  4ac))/2a
Vertex is derived from the sum of the xintercepts divided by 2.
1.46 + 1.14 = 0.16
Vertex input for x = 0.16
Sub back into equation to find the y input of the vertex
y= 3(0.16)^2  (o.16) +5
y = 1.12
Therefore the vertex is (0.16,1.12)