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April 24, 2014

April 24, 2014

Posted by **Nemo** on Thursday, September 29, 2011 at 4:35pm.

Find the y-intercepts, x-intercepts, and the vertex

- Math -
**Anonymous**, Thursday, September 29, 2011 at 5:36pmy = -3^2 - x + 5

y - int = 5

x- int = -1.46 and 1.14 (using the quadratic equation of x = (-b+/- sqrt(b^2 - 4ac))/2a

Vertex is derived from the sum of the x-intercepts divided by 2.

-1.46 + 1.14 = -0.16

Vertex input for x = -0.16

Sub back into equation to find the y- input of the vertex

y= -3(-0.16)^2 - (-o.16) +5

y = 1.12

Therefore the vertex is (-0.16,1.12)

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