I count 64 posibilitys: p=person s=seat
is that with the requirement that each couple sit side by side?
if the couples have to sit side by side then i count 32
In the first seat: There are 8 possibilites for who sits there.
In the second seat: There is only 1 possibility (the other member of the couple).
In the third seat: There are 6 possibilites for who sits there.
In the fourth seat: There is only 1 possibility (the other member of the couple).
In the fifth seat: There are 4 possibilities for who sits there.
In the sixth seat: There is only 1 possibility (the other member of the couple).
In the seventh seat: There are 2 possibilities for who sits there.
In the eighth seat: There is only 1 possibility (the last member of the last couple).
Answer: 8*1*6*1*4*1*2*1 = 384 different possibilities!
There are 384 possibilities.
uhhhhhhhh are you sure cause that doesn't sound posible. especialy if the couples have to sit side by side
i know u included the couples sitting side by side but still
Yes, if the couples were not required to sit next to each other then the number of possibilities would be (8*7*6*5*4*3*2*1) = 40,320. I've taken Statistics at Georgia Tech and this was the fun part!!
got it. Thanks so much.
there are six ways each of them can sit next to each of them sit. five to sit next to them. six times six = thirtysix
five times five = 30 add them together you get 66
Answer this Question
Data Management - At a banquet, 4 coupes are sitting along one side of a table ...
maths - All the students in a school are made to stand in rows so as to form an ...
math 12 - Find the number of seating arrangements of eight basketball players on...
Pre-Cal - Four couples have reserved seats in a row for a concert. How many ways...
math - Consider an equilateral triangle with points located at each vertex and ...
9th grade math - the triange is 31cm, side 1 and side 2 have equal lenghts, ...
A Geometry ? - Given that two sides of a triangle are 20 and 66. Find the range ...
Math - The teacher plans to assign 8 students to 8 desks for a debate. How many ...
statistics - n youth corp have to stand in a row if all possible permutations;...
math help - Can someone explain to me the following step by step , i 've looked ...