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Chemistry

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The solubility of a certain compound in ice-cold water is 0.22g in 100mL. Its solubility in hot water is 4.35g in 100mL What is the best possible percent recovery we can expect for the re-crystallization of this compound in water?

  • Chemistry - ,

    I worked this last night for another student and thought too little information was given. Here is another take on it.
    If we take a 4.35 g sample, it will require 100 mL of hot water to dissolve it. When it crystallizes in ice cold water, we lose 0.22 g of it. Therefore, we can recover 4.35-0.22 = 4.13g.
    %recovery = (4.13/4.35)*100 = x

  • Chemistry - ,

    Thank you so much drbob! Your explanation make sense! :D

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