Posted by Allison on .
Let f(x)=21−x^2
The slope of the tangent line to the graph of f(x) at the point (−4,5) is ______ .
The equation of the tangent line to the graph of f(x) at (−4,5) is y=mx+b for
m=______
and
b=_______.

Calculus 
Steve,
f(x) = 21x²
f'(x) = 2x
f'(4) = 8
The line through (4,5) with slope 8 is
(y5)/(x+4) = 8
y = 8x +37
I think that's enough of these.