Posted by **Allison** on Thursday, September 29, 2011 at 1:07pm.

For what values of x is the tangent line of the graph of

f(x)=8x3+36x2+46x−72

parallel to the line y=−2x+1.9 ? Enter the x values in order, smallest first, to 4 places of accuracy:

x1= ≤ x2=

- Calculus -
**Steve**, Thursday, September 29, 2011 at 3:00pm
f(x) = 8x³ + 36x² + 46x - 72

f'(x) = 24x² + 72x + 46

The slope of y = -2x+1.9 is -2

So, we want to find values of x where f'(x) = -2

24x² + 72x + 46 = -2

24x^2 + 72x + 48 = 0

x^2 + 3x + 2 = 0

(x+1)(x+2)

So, x = -2.0000, -1.0000

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