Posted by muthu on Thursday, September 29, 2011 at 5:40am.
the equation for the ball's height at time t will be
h = 2 + 80t - 16t^2
So, it will be 98' up when t = 2
h=0 when t = 5.025 sec
(at t=5, it will be back to its original 2' height)
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