Posted by Lola312 on .
An object is projected vertically upwards with a velocity of 28m/s. Two seconds later, another object is thrown vertically upwards with a velocity of 32 m/s. When and where will the two objects meet?

physics 
tchrwill,
Think about it.
In 2 seconds, the first object, traveling at 28m/s, is 56m high
Once the second object is thrown up at the speed of 32m/s, it will close in on the first object at the net speed of 32  28 = 4m/s.
You can now determine the time it takes for the second object to catch up to the first object and how far they have traveled. 
physics 
Leslie,
But you don't know at how many seconds the first object is projected upwards! Wouldn't you sub in those motion formulas for this type of question?