Posted by Lola312 on Wednesday, September 28, 2011 at 11:06pm.
Think about it.
In 2 seconds, the first object, traveling at 28m/s, is 56m high
Once the second object is thrown up at the speed of 32m/s, it will close in on the first object at the net speed of 32 - 28 = 4m/s.
You can now determine the time it takes for the second object to catch up to the first object and how far they have traveled.
But you don't know at how many seconds the first object is projected upwards! Wouldn't you sub in those motion formulas for this type of question?
But you don't know at how many seconds the first object is projected upwards! Wouldn't you sub in those motion formulas for this type of question?
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