Posted by **Marko** on Wednesday, September 28, 2011 at 9:47pm.

Mrs.Sue my homework from yesterday i had wrong instructions i needed to find the mean median and mode. not the outlier an affect. my teacher switched the assignment

can you check my answers i have to find the mean, median and mode

1)

8 12 6 9 5

mean: 8

median : 8

mode : no mode

2) 3.4 0.53 1.3 2.9 1.47 0.24

mean: 1.64

median : 1.385

mode: no mode

3) -6 3 -2 6 7 -3 -5 8

mean : 1

median : 1 (? not sure on that)

mode : no mode

4) -17 32 -9 0 52 12 -14

mean: 8

median: 0

mode no mode

5) 75 72 46 77 70 80 68

mean: 70.25

median : 73

mode: no mode

6) -15 -12 -19 0 -20 -14

mean: 13.33

median : 14.5

mode: no mode

7) 5.3 5.1 5.2 14.7 5.8 5.9 5.4

mean: 6.77

median: 5.4

mode: no mode

8) 4 -1 -16 2 0 -3 6 -2

mean: 1.25

median: -1

mode: no mode

- algebra help Ms. Sue -
**Ms. Sue**, Wednesday, September 28, 2011 at 9:58pm
Please note that my name is **Ms. Sue**.

Your first two answers are right. However, without commas or a list, I can't really determine what your problems are.

It looks as though you have the right idea for solving these mean and median problems.

- algebra help mrs. Sue -
**Marko**, Wednesday, September 28, 2011 at 10:18pm
quetion 3)

-6

3

-2

6

7

-3

-5

8

question 4)

-17

32

-9

0

52

12

-4

question 5)

75

72

74

46

77

70

80

68

question 6

-15

-12

-19

0

-20

-14

question 7

5.3

5.1

5.2

14.7

5.8

5.9

5.4

QUETION 8

-16

-3

-2

-1

0

2

4

6

- algebra help mrs. Sue -
**muthu**, Thursday, September 29, 2011 at 6:06am
3)there are two medians -2 and 3 , so the median is the mean of -2and 3, that's (-2+3)/2 = 1/2=0.5

mode is an average , you can not say there is no average for a given data , so here any value can be taken as the mode

8) the mean = -1.25

median = mean of -1 and 0= -1/2= -0.5

5) median = 72

and some more mistake are there i hope MARKO you will be able to correct it

bye :)

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