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November 22, 2014

November 22, 2014

Posted by **tatiana** on Wednesday, September 28, 2011 at 9:34pm.

- pre-calculus -
**Steve**, Thursday, September 29, 2011 at 5:44amDraw a perpendicular from the center of the circle to the chord.

So, now we have a central angle a, subtending the chord, such that

sin(a/2) = 12/13

Now the area of the minor segment is the area of the sector subtended by the chord, less the area of the triangle.

The height of the triangle is sqrt(13^2 - 12^2) = 5.

A = 1/2 r^2 * a - 1/2 * 24 * 5

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