Posted by **STEPHANIE ** on Wednesday, September 28, 2011 at 5:35pm.

A ship leaves port at 1:00 P.M. and sails in the direction N36°W at a rate of 25 mi/hr. Another ship leaves port at 1:30 P.M. and sails in the direction N54°E at a rate of 16 mi/hr.

(a) Approximately how far apart are the ships at 3:00 P.M.? (Round your answer to the nearest whole number.)

(b) What is the bearing, to the nearest degree, from the first ship to the second?

- Math -
**Writeacher**, Wednesday, September 28, 2011 at 5:45pm
Stephanie, if you would **stop** typing in all-caps and just put "Math" in the subject line, you'd probably receive help. Anyone who shouts at tutors and demands things, usually is not helped.

- I NEED URGENT HELP!!! -
**STEPHANIE **, Wednesday, September 28, 2011 at 5:49pm
ok, sorry, would you help me then, please

- I NEED URGENT HELP!!! -
**Reiny**, Wednesday, September 28, 2011 at 6:39pm
Did you make a diagram?

Did you realize that the angle between their paths is 90°

How easy is that ???

First ship goes for 2 hrs at 25 mph or distance = 50 miles

2nd ship goes for 1.5 hrs at 16 mph or distance = 24 miles

a) let x be the distance between them

x^2 = 50^2 + 24^2 = 3076

x = 55.46 km

Let the angle at the left of the triangle be Ø

tanØ = 24/50

Ø = appr 25.64°

Draw in horizontals and verticals at that vertex and you should be able to find the bearing between the two ships

- I NEED URGENT HELP!!! -
**STEPHANIE **, Wednesday, September 28, 2011 at 6:50pm
ok, thanks

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