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Posted by on Wednesday, September 28, 2011 at 4:54pm.

From a point 45 meters above level ground, a surveyor measures the angle of depression of an object on the ground at 68°. Approximate the distance from the object to the point on the ground directly beneath the surveyor. (Round your answer to two decimal places.)

  • trig - , Wednesday, September 28, 2011 at 4:58pm

    Hint: tan = height/width

  • trig - , Wednesday, September 28, 2011 at 5:02pm

    ok, would you be able to set up for me?

  • trig - , Wednesday, September 28, 2011 at 5:14pm

    HELLO???? WHATS THE ANSWER

  • trig - , Wednesday, September 28, 2011 at 11:48pm

    Well, draw a triangle! I mean, they only gave you two pieces of information. Can't see any way to use it?

    At the top of the cliff is point A. At the bottom of the cliff is point B. AB = 45m. Somewhere out along the ground is point C.

    Now, angle BAC is 68deg.
    BC/45 = tan(68)
    BC = 45 tan(68) = 45 * 2.475 = 111.38m

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