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Physics

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There are two forces on the 2.36 kg box in the overhead view of Fig. 5-31 but only one is shown. For F1 = 18.6 N, a = 11.4 m/s2, and θ = 26.7°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.)

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    a)
    Fnet = ma
    F1 + F2 = ma
    18.6N + F2 = 2.36(11.4*cos26.7° + 11.4*sin26.7°)
    F2 = 42.6i + 12.1j

    b)
    sqrt(42.6^2 +12.1^2)
    = 44.3 (N)

    c)
    θ = 26.7° + 90°
    θ = -116.7°

  • Physics -

    a)
    Fnet = ma
    F1 + F2 = ma
    18.6N + F2 = 2.36(11.4*cos26.7° + 11.4*sin26.7°)
    F2 = 42.6i + 12.1j

    b)
    sqrt(42.6^2 +12.1^2)
    = 44.3 (N)

    c)
    θ = 26.7° + 180°
    θ = 206.7°

    206.7° - 300°
    θ = -93.3°

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