Friday

December 19, 2014

December 19, 2014

Posted by **Kayla** on Wednesday, September 28, 2011 at 12:56pm.

A. Find the magnitude m/s

B. Find the direction ° (above the horizontal)

- Physics -
**tchrwill**, Wednesday, September 28, 2011 at 1:57pmFor a projectile fired at an angle of µº to the horizontal with a velocity of Vm/s, the maximum height reached derives from h = V^2(sin^2(µ))/29 and the distance traveled parallel to the ground derives from d = V^2(sin(2µ))/g

1--Vcos(µ) = 50/2.75 = 18.181818

2--Vsin(µ) = 9.8(2.75) = 26.95

3--Vsin(µ)/Vcos(µ) = 26.95/18.18 = 1.48239

4--(µ) = arctan(1.48239) = 56º

5--Therefore, the initial launch velocity is V = 18.1818/cos(56) = 32.51m/s in the direction of 56º above the horizontal.

I hope this has been of some help to you.

**Answer this Question**

**Related Questions**

physics - A ball launched from ground level lands 3 s later on a level field 48 ...

physics - A ball launched from ground level lands 2.15 s later on a level field ...

physics - A golf ball is struck with a five iron on level ground. It lands 92.7 ...

Physics - A golf ball is struck with a five iron on level ground. It lands 85.0 ...

physics - A projectile is launched over level ground at a launch angle of 70o ...

johnny - A projectile is launched over level ground at a launch angle of 70o ...

Physics - A ball thrown into the air lands on the same horizontal level, 31 m ...

physics - A projectile is launched at an angle of 58.5 degrees above the ...

Physics 1 - A golf ball is struck with a five iron on level ground. It lands 92....

AP physics - A NFL punter kicks a ball and lands 52 m away and is in the air ...