Posted by vianey on Tuesday, September 27, 2011 at 11:56pm.
Let ones=x
tens=y
hundreds=z
thousands=a
a+x+y+z=15
x=1+y
y=a+1
z=x+a
y=3
x=1+(3)
x=4
(3)=a+1
a=2
z=(4)+(2)
z=6
2634
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